SOLUTION: 0ut of 800 families with 4 children each, how many families would be expected to have (i) 2 boys and 2 girls (ii) at least one boy (iii) at most 2 girls (iv) children of both sexe

Algebra ->  Probability-and-statistics -> SOLUTION: 0ut of 800 families with 4 children each, how many families would be expected to have (i) 2 boys and 2 girls (ii) at least one boy (iii) at most 2 girls (iv) children of both sexe      Log On


   



Question 829400: 0ut of 800 families with 4 children each, how many families would be expected to have (i) 2 boys and 2
girls (ii) at least one boy (iii) at most 2 girls (iv) children of both sexes. Assume equal probability for
boys and girls.

Answer by oscargut(2103) About Me  (Show Source):
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Solution
i) 800 P(2 boys and 2 girls) = 800 C(4,2)(1/2)^2(1/2)^2 = 800(6/16) = 300
Answer 300

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