SOLUTION: a rectangle with perimeter of 52 inches has a length to width ratio of 8 to 5. find the length and width of the rectangle
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-> SOLUTION: a rectangle with perimeter of 52 inches has a length to width ratio of 8 to 5. find the length and width of the rectangle
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2x + 2y = 52
x/y = 8/5
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put the system of linear equations into standard form:
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2x + 2y = 52
5x = 8y
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2x + 2y = 52
5x - 8y = 0
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solution:
x = length = 16 in
y = width = 10 in
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