SOLUTION: solve the equation log(x-6)+log(x-3)=1. List any extraneous roots.

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Question 829074: solve the equation log(x-6)+log(x-3)=1. List any extraneous roots.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve the equation log(x-6)+log(x-3)=1. List any extraneous roots.
log%28%28x-6%29%29%2Blog%28%28x-3%29%29=1
log%28%28%28x-6%29%28x-3%29%29%29=1
10^1=(x-6)(x-3)
x^2-9x+18=10
x^2-9x+8=0
(x-1)(x-8)=0
x=1(reject,(x-3)>0))
or
x=8