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| Question 829011:  consider the line y=7/2x-5
 Find the equation of the line that is perpendicular to this line and passes through the point (7,-3)
 Find the equation of the line that is parallel to this line and passes through the point (7,-3)
 Answer by TimothyLamb(4379)
      (Show Source): 
You can put this solution on YOUR website! --- given:
 line: y=7/2x-5
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 find perpendicular line passing through: (7,-3)
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 perpendicular slope = -2/7 = -0.285714285714286
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 to solve the linear equation, copy and paste this (the given point and perpendicular slope):
 7,-3,-0.285714285714286
 into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
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 x-intercept = (-3.5, 0)
 y-intercept = (0, -1)
 slope = -2/7
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 answer:
 the slope-intercept form of our new perpendicular line:
 y = (-2/7)x - 1
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 find parallel line passing through: (7,-3)
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 parallel slope = 7/2 = 3.500000000000000
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 to solve the linear equation, copy and paste this (the given point and parallel slope):
 7,-3,3.500000000000000
 into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
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 x-intercept = (7.85714286, 0)
 y-intercept = (0, -27.5)
 slope = 7/2
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 answer:
 the slope-intercept form of our new parallel line:
 y = (7/2)x - 27.5
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