Question 828983: 3 consecutive even integers such that the sum of the squares of the first and second integer is equal to the square of the third integer plus 20
Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! consecutive even integers: (x-2), x, (x+2)
(x-2)^2 + x^2 = (x+2)^2 + 20
x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 + 20
x^2 - 4x = 4x + 20
x^2 - 8x - 20 = 0
(x - 10)(x + 2) = 0
x = 10, x = -2
The integers could be {-4, -2, 0} or {8, 10, 12}.
|
|
|