SOLUTION: 3 consecutive odd integers such that two times the sum of all three is nine less than the product of the first and second integer

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Question 828982: 3 consecutive odd integers such that two times the sum of all three is nine less than the product of the first and second integer
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

2((x-2) + x + (x+2)) = (x-2)(x) - 9
2(3x) = x^2 - 2x - 9
6x = x^2 - 2x - 9
0 = x^2 - 8x - 9
0 = (x - 9)(x + 1)
x = 9 or x = -1

The integers could be {7, 9, 11} or {-3, -1, 1}.