Question 828966: Of 1000 employees in a company, 250 are males and 750 are females. A total of 200 of the male and 400 of the female employees are in favor of a proposed paying scheme. If an employee is chosen at random, what is the probability that:
a) the employee is a male and is in favor
b) the employee is not in favor and is a famale
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Of 1000 employees in a company, 250 are males and 750 are females. A total of 200 of the male and 400 of the female employees are in favor of a proposed paying scheme. If an employee is chosen at random, what is the probability that:
a) the employee is a male and is in favor
P(male and in favor) = P(favor |male)P(male) = (200/250)(250/1000) = 1/5
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b) the employee is not in favor and is a famale
= P(favor and female) = P(favor |female)*P(female) = (450/750)(750/1000)= 9/20
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Cheers,
Stan H.
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