SOLUTION: I already posted one question and i had some idea of that one, but this one completely confuses me. {{{ (x-7+(12/x))/(x-5+(6/x)) }}} i do not understand how to simplify this one. p

Algebra ->  Expressions-with-variables -> SOLUTION: I already posted one question and i had some idea of that one, but this one completely confuses me. {{{ (x-7+(12/x))/(x-5+(6/x)) }}} i do not understand how to simplify this one. p      Log On


   

Question 82876: I already posted one question and i had some idea of that one, but this one completely confuses me. +%28x-7%2B%2812%2Fx%29%29%2F%28x-5%2B%286%2Fx%29%29+ i do not understand how to simplify this one. please assist me. thanks a bunch.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
+%28x-7%2B%2812%2Fx%29%29%2F%28x-5%2B%286%2Fx%29%29+ Start with the given expression

+%28x%2Fx%29%28%28x-7%2B%2812%2Fx%29%29%2F%28x-5%2B%286%2Fx%29%29%29+ Multiply both top and bottom by x

+%28x%5E2-7x%2B12%29%2F%28x%5E2-5x%2B6%29+ Distribute each x

Now factor the top and bottom individually

Factor the numerator
ERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'quadratic_factoring'.
Error occurred executing solver 'quadratic_factoring' .



Factor the denominator

ERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'quadratic_factoring'.
Error occurred executing solver 'quadratic_factoring' .




So we after factoring we get:

%28%28x-3%29%28x-4%29%29%2F%28%28x-2%29%28x-3%29%29

%28cross%28%28x-3%29%29%28x-4%29%29%2F%28%28x-2%29cross%28%28x-3%29%29%29 Cancel like terms

So everything reduces to:

%28x-4%29%2F%28x-2%29