|  | 
| 
 
 
| Question 828715:  find the slope-intercept equation of the line with the following properties perpendicular to the line x-7y=5; containing the point (3,3).
 Answer by TimothyLamb(4379)
      (Show Source): 
You can put this solution on YOUR website! --- given:
 (3,3)
 x-7y=5
 ---
 7y = x - 5
 y = (1/7)x - 5/7
 ---
 perp slope = -7
 ---
 to solve the linear equation, copy and paste this (the given point and perpendicular slope):
 3, 3, -7
 into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
 ---
 x-intercept = (3.42857143, 0)
 y-intercept = (0, 24)
 slope = -7
 ---
 answer:
 the slope-intercept form of our new line:
 y = -7x + 24
 ---
 Solve and graph linear equations:
 https://sooeet.com/math/linear-equation-solver.php
 ---
 Solve quadratic equations, quadratic formula:
 https://sooeet.com/math/quadratic-formula-solver.php
 ---
 Solve systems of linear equations up to 6-equations 6-variables:
 https://sooeet.com/math/system-of-linear-equations-solver.php
 | 
  
 | 
 |  |  |