Question 828706: How many liters of a 20% solution of a chemical should be mixed with 15L of a 50% solution to get a 30% mixture? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
20x + 50y = 30(x + y)
y = 15
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put the system of linear equations into standard form:
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20x + 50y = 30x + 30y
y = 15
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10x - 20y = 0
y = 15
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answer:
x = 30 liters of 20%
y = 15 liters of 50%
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resulting solution: 45 liters of 30%
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