Question 828455: The question I'd like to ask is (5.3.2):
Solve the equation of 2cosx - 1 = 0
I know that I should have a set of two "x =" solutions, but need some help after that. I thought the answer might be "x = (pi/3) + 2*n*pi and x = (5pi/3)+2*n*pi (where n is an integer)", but am second guessing myself; I think it is close to that, but I might have a value or two off. If you could show me the answer, as well as how you go that answer, it would be much appreciated.
Answer by MathTherapy(10557)   (Show Source):
You can put this solution on YOUR website! The question I'd like to ask is (5.3.2):
Solve the equation of 2cosx - 1 = 0
I know that I should have a set of two "x =" solutions, but need some help after that. I thought the answer might be "x = (pi/3) + 2*n*pi and x = (5pi/3)+2*n*pi (where n is an integer)", but am second guessing myself; I think it is close to that, but I might have a value or two off. If you could show me the answer, as well as how you go that answer, it would be much appreciated.
2 cos x - 1 = 0
2 cos x = 1 ------ Adding 1 to both sides
1st Quadrant:  or 
4th Quadrant:  or 
You can do the check!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,
GENERAL MATH QUESTIONS, MATH HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE, GRE, CLEP,
and the GED, you can visit: http://asvabstudyzone.freeforums.net/.
|
|
|
