SOLUTION: One angle of a triangle is 2/3rd of a right angle and the greater of the other two exceeds to the less by 18 degree. Find the angle in degree!

Algebra ->  Polygons -> SOLUTION: One angle of a triangle is 2/3rd of a right angle and the greater of the other two exceeds to the less by 18 degree. Find the angle in degree!       Log On


   



Question 828423: One angle of a triangle is 2/3rd of a right angle and the greater of the other two exceeds to the less by 18 degree. Find the angle in degree!

Found 2 solutions by stanbon, LinnW:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
One angle of a triangle is 2/3rd of a right angle and the greater of the other two exceeds to the less by 18 degree. Find the angle in degree!
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1st: (2/3)90 = 60 degrees
2nd: x
3rd x + 18
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Equation:
x + x+18 + 60 = 180
2x = 102
x = 51 degrees
x+18 = 69 degrees
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Cheers,
Stan H.

Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
2/3 of right angle is 2/3 of 90 or 60
The remaining two angles total 120 since the sum of the 3 needs to be 180
Set x = one angle
set (x+18) = the other angle
x + (x+18) = 120
2x + 18 = 120
subtract 18 from each side
2x = 102
x = 51
(x+18) = 51+18 = 69
So the angles are 60 51 and 69 .