SOLUTION: An automobile radiator contains 10 qt of a mixture of water and antifreeze that is 20% antifreeze. How much of this mixture must be drained out and replaced with pure antifreeze in
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Question 828379: An automobile radiator contains 10 qt of a mixture of water and antifreeze that is 20% antifreeze. How much of this mixture must be drained out and replaced with pure antifreeze in order to obtain a 50% mixture in the radiator? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
x = volume of 100% antifreeze
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20*10 + 100x = 50(x + 10)
200 + 100x = 50x + 500
50x = 300
x = 300/50
x = 6
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drain 6 quarts and replace that volume with 100% antifreeze
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