SOLUTION: A jet leaves an airport traveling at a steady rate of 600 km/h. Another jet leaves the same airport 3/4 h later traveling at 800 km/h in the same direction. How ling will it take t
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Question 828368: A jet leaves an airport traveling at a steady rate of 600 km/h. Another jet leaves the same airport 3/4 h later traveling at 800 km/h in the same direction. How ling will it take the second jet to overtake the first? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
s = d/t
t = d/s
d = s*t
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jet-1's head start:
d = 600 * 0.75
d = 450 km
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jet-2 speed relative to jet-1:
s = 800 - 600
s = = 200 kph
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time to overtake relative to jet-2:
t = d/s
t = 450/200
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answer-1:
t = 2.25 hours
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solution by a different method:
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D = distance from airport at which the overtake occurs:
t = time the overtake occurs, relative to jet-2
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overtake distance relative to jet-1:
D = 600(t + 0.75)
D = 600t + 600*0.75
D = 600t + 450
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overtake distance relative to jet-2:
D = 800t
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time to overtake relative to jet-2:
D = D
substitute the above expressions for D:
600t + 450 = 800t
200t = 450
t = 450/200
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answer-2:
t = 2.25 hours
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NOTE:
the overtake will occur 2 hours and 15 minutes after the second jet departs.
this result is confirmed using two different methods.
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