SOLUTION: Given that cos(theta) = m/n, find the value of cos^2(theta) - 1

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Question 828154: Given that cos(theta) = m/n, find the value of cos^2(theta) - 1
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Given that cos(theta) = m/n, find the value of cos^2(theta) - 1
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cos^2(t) -1 = (m/n)^2-1
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= [m^2-n^2]/n^2
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Cheers,
Stan H.
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