SOLUTION: Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third

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Question 828121: Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First integer : N
Next two consecutive integers : N%2B1,N%2B2
The sum of first and twice the second : N+%2B+2%2A%28N%2B1%29
is means "equals"
80 minus three times the third : 80-3%2A%28N%2B2%29
So then,
N%2B+2%2A%28N%2B1%29=80-3%2A%28N%2B2%29
N%2B2N%2B2=80-3N-6
I leave you that to solve for N.
Re-post if you still need help.