SOLUTION: I need not only answer,but solution too: In 4 years from now Anna will be 2/3 (two thirds) of Berzot’s present age. In 11 years from now Berzot will be double Sasha’s present a

Algebra ->  Finance -> SOLUTION: I need not only answer,but solution too: In 4 years from now Anna will be 2/3 (two thirds) of Berzot’s present age. In 11 years from now Berzot will be double Sasha’s present a      Log On


   



Question 828052: I need not only answer,but solution too:
In 4 years from now Anna will be 2/3 (two thirds) of Berzot’s present age. In 11 years from
now Berzot will be double Sasha’s present age. 14 years ago Sasha was half Anna’s present
age. Find their present ages.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = Anna's age now
Let +b+ = Berzot's age now
Let +s+ = Sasha's age now
--------------------------
(1) +a+%2B+4+=+%282%2F3%29%2Ab+
(2) +b+%2B+11+=+2s+
(3) +s+-+14+=+%281%2F2%29%2Aa+
-----------------------
You have 3 equations and 3 unknowns,
so it is solvable
(1) +3a+%2B+12+=+2b+
(1) +-3a+%2B+2b+=+12+
---------------------
(2) +b+=+2s+-+11+
-------------------
(3) +2s+-28+=+a+
(3) +2s+-+a+=+28+
------------------
Substitute (2) into (1)
(1) +-3a+%2B+2%2A%28+2s+-+11+%29+=+12+
(1) +-3a+%2B+4s+-+22+=+12+
(1) +4s+-+3a+=+34+
--------------------
Multiply both sides of (3) by 2 and
subtract (1) from (3)
(3) +4s+-+2a+=+56+
(1) +-4s+%2B+3a+=+-34+
+a+=+22+
-------------
(1) +-3a+%2B+2b+=+12+
(1) +-3%2A22+%2B+2b+=+12+
(1) +-66+%2B+2b+=+12+
(1) +2b+=+78+
(1) +b+=+39+
---------------
(3) +2s+-+a+=+28+
(3) +2s+-+22+=+28+
(3) +2s+=+50+
(3) +s+=+25+
----------------
Anna's age is 22
Berzot's age is 39
Sasha's age is 25
----------------
check:
(1) +a+%2B+4+=+%282%2F3%29%2Ab+
(1) +22+%2B+4+=+%282%2F3%29%2A39+
(1) +26+=+%282%2F3%29%2A39+
(1) +78+=+2%2A39+
(1) +78+=+78+
OK- you can check (2) and (3)