Question 82793: could someone please at least tell me the steps to solve to this problem. my math book read like high level instructions.
find a rational function that has x=-3 and x=5 as vertical asymptotes, y=2 as a horzontal asymptote and (3,0) as an x intercept
that is the problem but i can not make sense of the math book if someone could help i would greatly appreciate it!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find a rational function that has x=-3 and x=5 as vertical asymptotes
So the denominator contains (x+3) and (x-5)
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, y=2 as a horzontal asymptote and (3,0) as an x intercept
so the numerator conains a factor of 2x^2
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Comment: so far the function looks like
f(x) = 2x^2/[(x+3)(x-5)]
and (3,0) as an x intercept
So, it neets a factor of (x-3) in the numerator.
That reduces the need for x^2 in the numerator; x will do the job.
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Final Answer: f(x) = [2x(x-3)]/[(x+3)(x-5)]
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Cheers,
Stan H.
f(x) =
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