SOLUTION: Please help me solve this equation. Find the quotient of (2-3i) (1+i)

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Question 827926: Please help me solve this equation. Find the quotient of (2-3i) (1+i)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the quotient of %282-3i%29 and +%281%2Bi%29+: %282-3i%29%2F%281%2Bi%29

+%282-3i%29%2F%281%2Bi%29+ ...........both numerator and denominator multiply by +%281-i%29+

%28%282-3i%29%281-i%29%29%2F%28%281%2Bi%29%281-i%29%29+

%28%282-3i%29%281-i%29%29%2F%281%5E2-i%5E2%29+ ...since i=sqrt%28-1%29=> i%5E2=%28sqrt%28-1%29%29%5E2=-1, so we have

%28%282-3i%29%281-i%29%29%2F%281-%28-1%29%29+

%28%282-3i%29%281-i%29%29%2F%281%2B1%29+

%28%282-3i%29%281-i%29%29%2F2+ ..................now do numerator

%28%282%2A1-3i%2A1%2B2%28-i%29-3i%28-I%29%29%29%2F2+

%282-3i-2i%2B3i%5E2%29%2F2+

%282-5i%2B3%28-1%29%29%2F2+

%282-5i-3%29%2F2+

%28-1-5i%29%2F2+

-1%2F2-5i%2F2+