SOLUTION: how do you find a numerical value of the trig function.....2sin^2x=3cos^2x

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Question 827735: how do you find a numerical value of the trig function.....2sin^2x=3cos^2x
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
2sin%5E2%28x%29%22%22=%22%223cos%5E2%28x%29

Divide both sides by 2cos%5E2%28x%29

%282sin%5E2%28x%29%29%2F%282cos%5E2%28x%29%29%22%22=%22%223cos%5E2%28x%29%2F%282cos%5E2%28x%29%29

%28cross%282%29sin%5E2%28x%29%29%2F%28cross%282%29cos%5E2%28x%29%29%22%22=%22%22%283cross%28cos%5E2%28x%29%29%29%2F%282cross%28cos%5E2%28x%29%29%29

%28sin%5E2%28x%29%29%2F%28cos%5E2%28x%29%29%22%22=%22%223%2F2

%28sin%28x%29%2Fcos%28x%29%29%5E2%22%22=%22%223%2F2

tan%5E2%28x%29%22%22=%22%223%2F2

tan%28x%29%22%22=%22%22%22%22%2B-+sqrt%283%2F2%29

in degrees, %220%B0%22+%3C=+x+%3C+%22360%B0%22, 50.76847952°, 129.2315205°, 230.7684795°, 309.2315205°

In radians, 0%3C=x%3C2pi, 0.8860771238, 2.25551553, 4.027669777, 5.397108183, 5.397108183  

Edwin