SOLUTION: . A conic has focus at (0, 0) and directrix at x = −1. The point (4, 3) lies on the conic. Hence determine the eccentricity of the conic, and state whether it is an ellipse

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: . A conic has focus at (0, 0) and directrix at x = −1. The point (4, 3) lies on the conic. Hence determine the eccentricity of the conic, and state whether it is an ellipse      Log On


   

Question 827611: . A conic has focus at (0, 0) and directrix at x = −1. The point (4, 3) lies on the
conic. Hence determine the eccentricity of the conic, and state whether it is an
ellipse, parabola or hyperbola.
Answer by lwsshak3(11628) About Me  (Show Source):
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A conic has focus at (0, 0) and directrix at x = −1. The point (4, 3) lies on the conic. Hence determine the eccentricity of the conic, and state whether it is an ellipse, parabola or hyperbola.
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focus and directrix shows axis of symmetry: y=0, or x-axis
directrix of x=-1 shows conic is a parabola that opens right.
Its basic equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex
p=1/2
4p=2
vertex:(0,-1/2) Eccentricity does not apply to parabolas.
Equation of given conic: y^2=2(x+1/2)