Question 827535: A base ball is hit from a tee, and its height in feet above the ground is modeled by the function h(t)=-16t^2+120t+3, where t represents the time is seconds after the ball is hit. How long is the ball in the air and what is its maximum height?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
h(t) = -16t^2 + 120t + 3
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the above quadratic equation is in standard form, with a=-16, b=120, and c=3
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
-16 120 3
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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t = -0.0249172176
t = 7.52491722
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negative time doesn't fit the problem statement, so use the positive root:
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answer1:
the ball is in flight 7.525 seconds
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the quadratic vertex is a maximum at: ( t= 3.75, h= 228 )
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answer2:
the ball reaches a maximum height of 228 ft
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