Question 827531: A soccer ball is kicked from the ground, and its height in meters above ground is modeled by the function h(t)=-4.9t^2+19.6t, where t represents the time in seconds after the ball is kicked. How long is the ball higher then 10 meters.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
h(t) = -4.9t^2 + 19.6t
h(t) = -4.9t^2 + 19.6t = 10
h(t) = -4.9t^2 + 19.6t - 10 = 0
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the above quadratic equation is in standard form, with a=-4.9, b=19.6, and c=-10
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
-4.9 19.6 -10
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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t = 0.600291576
t = 3.39970842
dt = 3.39970842 - 0.600291576
dt = 2.799416844000000
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answer:
the ball is above 10 meters height for 2.8 seconds
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