SOLUTION: 2log4+2logx=log32

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Question 82737: 2log4+2logx=log32
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
2log4%2B2logx=log32
log+4%5E2+%2B+log+x%5E2+=+log+32
log+16+%2B+log+x%5E2+=+log+32
log+16x%5E2+=+log+32+

+16x%5E2+=+32
+x%5E2+=+2
x=+sqrt%282%29

(NOTE: x=-sqrt%282%29+ is NOT a valid solution, since you can't have a log of a negative number!)

Final answer: x=+sqrt%282%29+

R^2 at SCC