SOLUTION: I have two different solutions of sulfuric acid, one with 75% acid and one with 45% acid. If I want to end up with 250ml of 50% acid solution, how much of each solution do I need t
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Question 827286: I have two different solutions of sulfuric acid, one with 75% acid and one with 45% acid. If I want to end up with 250ml of 50% acid solution, how much of each solution do I need to use? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! I have two different solutions of sulfuric acid, one with 75% acid and one with 45% acid. If I want to end up with 250ml of 50% acid solution, how much of each solution do I need to use?
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Equation:
acid + acid = acid
0.75x + 0.45(250-x) = 0.50*250
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75x + 45*250 - 45x = 50*250
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30x = 5*250
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x = 41 2/3 ml (amt. of 75% solution needed)
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250-41 2/3) = 208 1/3 ml (amt. of 45% solution needed)
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Cheers,
Stan H.
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