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Question 827000: Find an equation of the line that passes through the given point and is perpendicular to the given line. Write the equation in slope-intercept form.
(6, -2), 5x = 7y - 4
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
given:
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point (6, -2)
slope perpendicular to: 5x = 7y - 4
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7y = 5x + 4
y = (5/7)x + (4/7)
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perpendicular slope = -(7/5) = -1.4
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to solve the linear equation, copy and paste this (the given point and perpendicular slope):
6, -2, -1.4
into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
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x-intercept = (4.57142857, 0)
y-intercept = (0, 6.4)
slope = -1.4
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answer:
the slope-intercept form of our new line:
y = -1.4x + 6.4
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Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 6-equations 6-variables:
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