SOLUTION: I am supposed to solve by substitution. My equations are
3/4x + 1/2y = -7/12
and
x - y = -4/3
I have tried getting x alone on the first question but can't get the right
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-> SOLUTION: I am supposed to solve by substitution. My equations are
3/4x + 1/2y = -7/12
and
x - y = -4/3
I have tried getting x alone on the first question but can't get the right
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Question 826630: I am supposed to solve by substitution. My equations are
3/4x + 1/2y = -7/12
and
x - y = -4/3
I have tried getting x alone on the first question but can't get the right answer Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
3/4x + 1/2y = -7/12
x - y = -4/3
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put the system of linear equations into standard form:
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( 3/4x + 1/2y = -7/12 ) 12
( x - y = -4/3 ) 3
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9x + 6y = -7
3x - 3y = -4
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution by matrix method:
x = -1
y = 0.33333333 = 1/3
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system matrix
9 6
3 -3
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inverse of system matrix
0.066666667 0.13333333
0.066666667 -0.2
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determinant of system matrix = -45
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now solve by substitution method:
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6y = -7 - 9x
y = -(7/6) - (9/6)x
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substitute into:
3x - 3y = -4
3x - 3( -(7/6) - (9/6)x ) = -4
3x + (7/2) + (9/2)x = -4
3x + (9/2)x = -4 - (7/2)
(6/2)x + (9/2)x = -(8/2) - (7/2)
( (6/2)x + (9/2)x = -(8/2) - (7/2) ) 2
15x = -15
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x = -1
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y = -(7/6) - (9/6)x
y = -(7/6) - (9/6)(-1)
y = -(7/6) + (9/6)
y = 2/6
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y = 1/3
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solution by substitution method:
x = -1
y = 0.33333333 = 1/3
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both methods agree!
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