| 
 
 
| Question 826561:  Please help me solve this problem:
 In a driving school, the time taken by student drivers to complete a full circuit of the test course was found to be normally distributed with a mean of 45 minutes and a standard deviation of 10 minutes.
 (i)	What proportion of students will complete the circuit in one hour?
 (ii)	How long should the driving lessons last so that 95% of students will have finished the circuit by the end of their lesson?
 
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! In a driving school, the time taken by student drivers to complete a full circuit of the test course was found to be normally distributed with a mean of 45 minutes and a standard deviation of 10 minutes. (i) What proportion of students will complete the circuit in one hour?
 -----
 z(60) = (60-45)/10 = 1.5
 P(x <= 60) = P(z < 1.5) = normalcdf(-100,1.5) = 0.1295 = 1295/10,000
 ==================================
 (ii) How long should the driving lessons last so that 95% of students will have finished the circuit by the end of their lesson?
 invNorm(0.95) = 1.645
 Use x = z*s+u
 time = 1.645*10+45 = 16.45+45 = 61.45 minutes.
 ===============
 Cheers,
 Stan H.
 ===============
 
 | 
  
 | 
 |