Question 826521: please help me solve this problem
find four consecutive even integers such that four times the greatest is 36 more than the sum of the other three
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! let x be the first even integer, then x, x+2, x+4, x+6 represent our four consecutive even integers, we are given
4 * (x+6) = x +(x+2) +(x+4) + 36
4x +24 = 3x +42
x = 18, therefore our four consecutive even integers are
18, 20, 22, 24
check our answer
4 * (18+6) = 18 +(18+2) +(18+4) +36
96 = 18 +20 +22 +36
96 = 96
our answer checks
|
|
|
