SOLUTION: -This winter, Mr.walker was out playing in the snow with the Walker-lers. The snow was great packing snow for snowballs, so they gathered up some neighbors and started to have frie

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: -This winter, Mr.walker was out playing in the snow with the Walker-lers. The snow was great packing snow for snowballs, so they gathered up some neighbors and started to have frie      Log On


   



Question 826024: -This winter, Mr.walker was out playing in the snow with the Walker-lers. The snow was great packing snow for snowballs, so they gathered up some neighbors and started to have friendly snowball fight. Mr.Walker went inside a friends apartment with a bucket of snowballs and started to launch them from the 4th floor window. He began to gather data on the snowball path so that he could have more accuracy when he threw them. One of the snowballs had a height(in feet)from the ground that followed the equation of h%28t%29+=+-16t%2B48t%2B64 where t represents time in seconds. In the real world ,what is the singnifivance of the y-intercept(s) in the situation ?
Answer by Fermat(136) About Me  (Show Source):
You can put this solution on YOUR website!
Your equation should look more like this:
h%28t%29=64+%2B+48t+-+16t%5E2
This is the equation of the height, above the ground, of am item that has been given an upward speed of 48 ft/s and begins its movement at a height of 64 ft above the ground.
The "y-intercept" is the value of y when the other variable equals zero.
When t = 0, h = 64.
i.e. the snowball is thrown from the building at t = 0, and at t = 0, h = 64 ft.
The graph of the equation looks like that below.
graph%28300%2C200%2C0%2C4%2C0%2C100%2C64+%2B+48%2Ax-16%2Ax%5E2%29