SOLUTION: divide 95 into two parts such that one half of the first part exceeds one fifth of second part by 16 kindly help me to solve it with required steps/details.
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Question 826013: divide 95 into two parts such that one half of the first part exceeds one fifth of second part by 16 kindly help me to solve it with required steps/details. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! divide 95 into two parts such that one half of the first part exceeds one fifth of second part by 16
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Using 2 variables::
Equations:
x + y = 95
(1/2)x - (1/5)y = 16
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Modify:
x + y = 95
5x - 2y = 160
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Modify:
5x + 5y = 475
5x - 2y = 160
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Subtract and solve for "y":
7y = 315
y = 45
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The x = 95-45 = 50
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Cheers,
Stan H.
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