SOLUTION: i need help on solving for x in this problem, please help, thank you. ln(x+2)+ln(2x-1)=0

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Question 825922: i need help on solving for x in this problem, please help, thank you.
ln(x+2)+ln(2x-1)=0
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Property of Logarithms, log%28a%29%2Blog%28b%29=log%28ab%29

"ln()", means "natural logarithm of...", the base being the Euler Number, approx. 2.71828...

Two equivalent equation formulations are:
ln%28x%29=A is the same as e%5EA=x.


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Your equation gives you highlight_green%28e%5E0=%28x%2B2%29%282x-1%29%29.
Best if you understand how to obtain that, and better still if you can finish solving it. Say if you need further help.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
ln(x+2)+ln(2x-1)=0
-----
ln[(x+2)(2x-1)] = 0
----
2x^2 + 3x -2 = 1
------
2x^2 + 3x -3 = 0
------
x = [-3 +- sqrt(9-4*2*-3)]/4
------
x = [-3 +- sqrt(33)]/4
----
x = [-3 +- 5.74]/4
---
x = 0.6861
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Cheers,
Stan H.
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