SOLUTION: Add the following rational expressions and make sure you answer is simplified:
x^3-x^2-10x/x^2-8x+16 + -3x^2-6x+64/x^2-8x+16 =
What I have so far is: x^3-x^2-10x >> x(x^2-x-1
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Add the following rational expressions and make sure you answer is simplified:
x^3-x^2-10x/x^2-8x+16 + -3x^2-6x+64/x^2-8x+16 =
What I have so far is: x^3-x^2-10x >> x(x^2-x-1
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Question 82586: Add the following rational expressions and make sure you answer is simplified:
x^3-x^2-10x/x^2-8x+16 + -3x^2-6x+64/x^2-8x+16 =
What I have so far is: x^3-x^2-10x >> x(x^2-x-10) [here is where I got stuck]
x^2-8x+16 >> (x-4)(x-4)
x^2-8x+16 >> (x-4)(x-4) Found 2 solutions by stanbon, ankor@dixie-net.com:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! [x^3-x^2-10x/x^2-8x+16] + [-3x^2-6x+64/x^2-8x+16]
The denominators are the same so combine the numerators:
= [ x^3-4x^2-16x+64]/[(x-4)^2]
= [x^2(x-4)-16(x-4)]/[(x-4)^2]
= [(x-4)(x^2-16)]/[(x-4)^2
= [ (x-4)^2(x+4)]/[(x-4)^2]
Cancel the (x-5)^2 factors to get:
= x+4
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Cheers,
Stan H.
You can put this solution on YOUR website! Add the following rational expressions and make sure you answer is simplified: + =
:
They have the same denominators so write it:
: : remove brackets, factor denominator as you did
: ; group like terms
: ; combined like terms
: ; group and factor
: ; factor out (x-4)
: : (x^2-16) can be factored (difference of squares)
:
Cancel out both (x-4)'s and you have:
x + 4