SOLUTION: If sinθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ. F. -24/25 G. 8/5 (I chose this one and it was wrong) H.-12/25 J. 24/25 Sorry I foun

Algebra ->  Trigonometry-basics -> SOLUTION: If sinθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ. F. -24/25 G. 8/5 (I chose this one and it was wrong) H.-12/25 J. 24/25 Sorry I foun      Log On


   



Question 825715: If sinθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ.
F. -24/25
G. 8/5 (I chose this one and it was wrong)
H.-12/25
J. 24/25
Sorry I found the typo I submitted in one of my previous questions. So sorry about that.

Found 2 solutions by jim_thompson5910, MathTherapy:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm going to use x in place of θ

sin(x) = 4/5

sin^2(x) = 16/25 ... square both sides

-------------------------------------------------------

sin^2(x) + cos^2(x) = 1

16/25 + cos^2(x) = 1

cos^2(x) = 1 - 16/25

cos^2(x) = 25/25 - 16/25

cos^2(x) = (25 - 16)/25

cos^2(x) = 9/25

cos(x) = -sqrt(9/25) ... we are in quadrant II, so cos(x) < 0

cos(x) = -3/5

--------------------------------------------------------

sin(2x) = 2*sin(x)*cos(x)

sin(2x) = 2*(4/5)*(-3/5)

sin(2x) = (2/1)*(4/5)*(-3/5)

sin(2x) = (2*4*(-3))/(1*5*5)

sin(2x) = -24/25

Final Answer: sin(2x) = -24/25

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
If sinθ= 4/5 and θ terminates in Quadrant II, find the exact value of sin2θ.
F. -24/25
G. 8/5 (I chose this one and it was wrong)
H.-12/25
J. 24/25
Sorry I found the typo I submitted in one of my previous questions. So sorry about that.

sin θ = 4%2F5 = O%2FH
Since the opposite side (O) is 4 and the hypotenuse (H)is 5, the adjacent side (A) MUST = 3,
as this represents a 3-4-5 special triangle
Since θ terminates in the 2nd quadrant, where cos is < 0 (negative), we get:
cos θ = -+A%2FH+=+-+3%2F5
sin 2 θ = 2 sin θ cos θ (double-angle identity)
Therefore, sin 2 θ = 2%284%2F5%29%28-+3%2F5%29____-%282%284%29%283%29%29%2F%285%29%285%29____highlight_green%28-+24%2F25%29 (CHOICE H)