SOLUTION: 2) Maggie is pulling a sled with a force of 275 newtons by holding its rope at a 58 degree angle. Her brother is going to help by pushing the sled with a force of 320 newtons.
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-> SOLUTION: 2) Maggie is pulling a sled with a force of 275 newtons by holding its rope at a 58 degree angle. Her brother is going to help by pushing the sled with a force of 320 newtons.
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Question 825663: 2) Maggie is pulling a sled with a force of 275 newtons by holding its rope at a 58 degree angle. Her brother is going to help by pushing the sled with a force of 320 newtons.
Let a=275 newtons and b=320 newtons.
Determine the magnitude of the total resultant force of the sled, a+b.
You can put this solution on YOUR website! ---
ax = horizontal component of maggie's pull:
ay = vertical component of maggie's pull:
assume the brother is pushing the sled with a horizontal force only (zero vertical force):
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cosA = ax/a
ax = a * cosA
ax = 275 * cos(58)
ax = 145.727797664131344 N
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sinA = ay/a
ay = a * cosA
ay = 275 * sin(58)
ay = 233.213226443017135 N
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sum of forces:
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fx = ax + b
fx = 145.727797664131344 + 320
fx = 465.727797664131344 N
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fy = ay
fy = 233.213226443017135 N
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net force vector:
magnitude:
f = sqrt( fx*fx + fy*fy )
f = 520.855825065866043 N
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angle:
tanA = fy/fx
A = arctan( fy/fx )
A = 26.599421454705364 degrees
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answer:
resultant force = 520.9 N at 26.6 degrees
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