SOLUTION: the line containing H(2,2) and parallel to the graph of y=x-3 m= ? (1?) point slope form= ? slope intercept form= ? Standard Form= ? (x-y=3)

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: the line containing H(2,2) and parallel to the graph of y=x-3 m= ? (1?) point slope form= ? slope intercept form= ? Standard Form= ? (x-y=3)       Log On


   

Question 825606: the line containing H(2,2) and parallel to the graph of y=x-3
m= ? (1?)
point slope form= ?
slope intercept form= ?
Standard Form= ? (x-y=3)
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
If parallel, then slope is the same as the given line. m=1 for both lines when expressed in slope-intercept form, y=mx+b.

The line containing H(2,2) is y=x+b, and we find by through substituting the given point which is on y=x+b.
'
b=y-x
b=2-2
b=0
The sought line intersects the origin.
The line in slope-intercept form is simply y=x

The point-slope form comes from using definition of slope.
m=1=%28y-2%29%2F%28x-2%29
1%2A%28x-2%29=y-2
and the rest follows... but this form does not give you any great advantage, since for such line, you could say y-12=x-12, or any y-k=x-k.

You can find the standard form equation on your own.