SOLUTION: An arch is in the form of a semi ellipse. It is 50 metres wide at the base and has a height of 20 metres. How wide is the arch at the height of 18 metres above the base?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: An arch is in the form of a semi ellipse. It is 50 metres wide at the base and has a height of 20 metres. How wide is the arch at the height of 18 metres above the base?      Log On


   



Question 825217: An arch is in the form of a semi ellipse. It is 50 metres wide at the base and has a height of 20 metres. How wide is the arch at the height of 18 metres above the base?
Answer by stanbon(75887) About Me  (Show Source):
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An arch is in the form of a semi ellipse. It is 50 metres wide at the base and has a height of 20 metres. How wide is the arch at the height of 18 metres above the base?
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x^2/25^2 + y^2/20^2 = 1
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x^2/625 + y^2/400 = 1
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Solve for "x" if y = 18
x^2/625 + 18^2/400 = 1
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x^2/625 = 1-0.81
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x^2/625 = 0.19
x^2 = 118.75
x = 10.89 ft.
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Cheers,
Stan H.
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