Question 825142: [ A man is twice as old as his son. If 9 years ago the sum of their ages was 66 years, find their present ages. ] Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
x = man
y = son
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x = 2y
(x - 9) + (y - 9) = 66
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put the system of linear equations into standard form
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x - 2y = 0
x + y = 84
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solution:
x = man = 56
y = son = 28
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