SOLUTION: Two pipes p1 & p2 can fill a tank in 40 minutes and 60 minutes respectively.Both the taps are opened and after 10 minutes p1 was shut. In how much more time would the tank be full?

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Question 825010: Two pipes p1 & p2 can fill a tank in 40 minutes and 60 minutes respectively.Both the taps are opened and after 10 minutes p1 was shut. In how much more time would the tank be full?
A)30 minutes B)35 minutes
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Both pipes were used for 10 hours, and only pipe 2 was used for some unknown amount of time afterward. The amount of tank filled was 1. Let x = time in hours after the first 10 minutess.

First period: p1 and p2 together for 10 minutes.
Second period: p2 for x minutes.
Total Time: 1 tank.

Use the rate information as tanks per time.
p1 rate is 1/40 tanks per minute.
p2 rate is 1/60 tanks per minute
p1 and p2 together rate is 1%2F40%2B1%2F60=%283%2B2%29%2F120=5%2F120=highlight_green%281%2F24%29 tanks per minute.

You have from the key uniform rate idea, R*t=j meaning rate time time equals the amount of job. Specific to our example, highlight%28%281%2F24%2910%2B%281%2F60%29x=1%29.
SOLVE FOR x.