SOLUTION: Solve the equation (2x +3)(x-7) = 4(x-7)

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Question 824618: Solve the equation
(2x +3)(x-7) = 4(x-7)

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2-11x-21 = 4x-28
2x^2-15x+7 = 0
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 2x%5E2-15x%2B7, we can see that the first coefficient is 2, the second coefficient is -15, and the last term is 7.



Now multiply the first coefficient 2 by the last term 7 to get %282%29%287%29=14.



Now the question is: what two whole numbers multiply to 14 (the previous product) and add to the second coefficient -15?



To find these two numbers, we need to list all of the factors of 14 (the previous product).



Factors of 14:

1,2,7,14

-1,-2,-7,-14



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 14.

1*14 = 14
2*7 = 14
(-1)*(-14) = 14
(-2)*(-7) = 14


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -15:



First NumberSecond NumberSum
1141+14=15
272+7=9
-1-14-1+(-14)=-15
-2-7-2+(-7)=-9




From the table, we can see that the two numbers -1 and -14 add to -15 (the middle coefficient).



So the two numbers -1 and -14 both multiply to 14 and add to -15



Now replace the middle term -15x with -x-14x. Remember, -1 and -14 add to -15. So this shows us that -x-14x=-15x.



2x%5E2%2Bhighlight%28-x-14x%29%2B7 Replace the second term -15x with -x-14x.



%282x%5E2-x%29%2B%28-14x%2B7%29 Group the terms into two pairs.



x%282x-1%29%2B%28-14x%2B7%29 Factor out the GCF x from the first group.



x%282x-1%29-7%282x-1%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28x-7%29%282x-1%29 Combine like terms. Or factor out the common term 2x-1



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Answer:



So 2%2Ax%5E2-15%2Ax%2B7 factors to %28x-7%29%282x-1%29.



In other words, 2%2Ax%5E2-15%2Ax%2B7=%28x-7%29%282x-1%29.



Note: you can check the answer by expanding %28x-7%29%282x-1%29 to get 2%2Ax%5E2-15%2Ax%2B7 or by graphing the original expression and the answer (the two graphs should be identical).