SOLUTION: an airplane has a speed of 325 miles per hour in still air. if the plane flies directly south and encounters a 40 mph wind blowing directly east, what is the resultant speed of the

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Question 824517: an airplane has a speed of 325 miles per hour in still air. if the plane flies directly south and encounters a 40 mph wind blowing directly east, what is the resultant speed of the airplane.
Found 2 solutions by TimothyLamb, stanbon:
Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website!
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use a right triangle:
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a = 325 at 180 degrees (true north)
b = 40 at 90 degrees (true north)
h = (hypotenuse) is the airplane's velocity vector
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h = sqrt( a*a + b*b )
h = sqrt( 325*325 + 40*40 )
h = 327.452286600658795
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A = angle of h relative to a
tanA = opp/adj
tanA = 40/325
A = arctan( 40/325 )
A = 7.016501744722909 degrees (relative to a)
resultant angle = 180 - 7.016501744722909
resultant angle = 172.983498255277084
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answer:
the resultant velocity of the airplane is:
327.5 mph at 173 degrees (true north)
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Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
an airplane has a speed of 325 miles per hour in still air. if the plane flies directly south and encounters a 40 mph wind blowing directly east, what is the resultant speed of the airplane.
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In one hour the distance traveled will be::
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distance = sqrt[325^2+40^2] = 327.45 miles
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rate = 327.45 mph
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Cheers,
Stan H.