Question 824473: In the lab, Chang has two solutions that contain alcohol and is mixing them with each other. He uses 500 milliliters less of Solution A than Solution B. Solution A is 16% alcohol and Solution B is 10% alcohol. How many milliliters of Solution A does he use, if the resulting mixture has 76 milliliters of pure alcohol?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In the lab, Chang has two solutions that contain alcohol and is mixing them with each other. He uses 500 milliliters less of Solution A than Solution B. Solution A is 16% alcohol and Solution B is 10% alcohol. How many milliliters of Solution A does he use, if the resulting mixture has 76 milliliters of pure alcohol?
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Total amt. of liquid: x + (x-500) = 2x-500
Equation:
alch + alch = alch
0.16(x-500) + 0.10x = 76
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Multiply thru by 100
16x-16*500 + 10x = 100*76
26x = 7600+8000
26x = 15600
x = 600 ml (amt. of 10% solution needed)
x-500 = 100 ml (amt of 16% solution needed)
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Cheers,
Stan H.
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