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Question 824314: I need more detail solution:
A girl has orange, yellow and red sweets. She has exactly twice as many red than yellow sweets.
After eating fourteen orange sweets, she has two less orange than yellow sweets. Also, the
number of orange sweets now are 20% of the total number of sweets she had at the beginning.
How many sweets did she have at the beginning?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I need more detail solution:
A girl has orange, yellow and red sweets.
number = o + y + r
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She has exactly twice as many red as yellow.
number = o + y + 2y = o+3y
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After eating fourteen orange sweets, she has two less orange than yellow sweets.
o-14 = y-2
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Also, the number of orange sweets now are 20% of the total number of sweets she had at the beginning.
o-14 = (1/5)(o+3y)
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How many sweets did she have at the beginning?
Using o-14 = (1/5)(o+3y) and o-14 = y-2 you get::
5o-70 = o+3y
4o - 3y = 70
o = y+12
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Solve for "y":
4y+48-3y = 70
y = 22 (# of yellow sweets)
o = y + 12 = 34 (# of orange sweets)
r = 2y = 44 (# of red sweets)
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total number:: 22 + 34 + 44 = 100
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Cheers,
Stan H.
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