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Question 824270: [ If the product of two positive numbers is 28, and one number is 3 greater than the other, what are the two numbers? ]
Found 2 solutions by TimothyLamb, Alan3354:
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
xy = 28
y = x + 3
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xy = 28
x(x + 3) = 28
xx + 3x - 28 = 0
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the above quadratic equation is in standard form, with a=1, b=3, and c=-28
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 3 -28
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has two real roots (the x-intercepts), which are:
x = 4
x = -7
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the negative root doesn't abide the problem statement, so use the positive root:
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answer:
x = 4
y = 7
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! If the product of two positive numbers is 28, and one number is 3 greater than the other, what are the two numbers?
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Try pairs of factors of 28.
1*28 NG
2*14 NG
etc
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