SOLUTION: complete the ordered pairs so that each is a solution for the given equation. 3x+4y=12 - (0,),(,3/4),(0),(8/3,)

Algebra ->  Graphs -> SOLUTION: complete the ordered pairs so that each is a solution for the given equation. 3x+4y=12 - (0,),(,3/4),(0),(8/3,)      Log On


   



Question 82422: complete the ordered pairs so that each is a solution for the given equation.
3x+4y=12 - (0,),(,3/4),(0),(8/3,)

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Start with (0,y)
Plug in x=0

3%280%29%2B4y=12 Plug in x=0 (one of the given pairs)

0%2B4y=12 Multiply

4y=12

y=3 Divide both sides by 4

So we get one ordered pair (0,3)
---------------------------------------------------------------
Now lets work with (x,3/4)
Plug in y=3%2F4

3x%2B4%283%2F4%29=12 Plug in y=3%2F4 (one of the given pairs)

3x%2B3=12 Multiply

3x=9 Subtract 3 from both sides
x=3 Divide both sides by 3

So we get one ordered pair (3,3/4)
---------------------------------------------------------------

Now lets work with (x,0)
Plug in y=0

3x%2B4%280%29=12 Plug in y=0 (one of the given pairs)

3x%2B0=12 Multiply

3x=12
x=4 Divide both sides by 3

So we get one ordered pair (4,0)
---------------------------------------------------------------

Now lets work with (8/3,y)
Plug in x=8%2F3

3%288%2F3%29%2B4y=12 Plug in x=8%2F3 (one of the given pairs)

8%2B4y=12 Multiply

4y=4 Subtract 8 from both sides
y=1 Divide both sides by 3

So we get one ordered pair (8/3,1)
---------------------------------------------------------------

So to summarize, we have the ordered pairs as solutions:

(0,3), (3,3/4), (4,0), (8/3,1)