SOLUTION: A COMPANY WANTS TO PRODUCE 500 GALLONS OF A 10% ALCOHOL SOLUTION BY MIXING AN UNKNOWN AMOUNT OF A 27% ALCOHOL SOLUTION WITH WATER. HOW MUCH WATER AND HOW MUCH 27% ALCOHOL SOLUTION

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Question 824096: A COMPANY WANTS TO PRODUCE 500 GALLONS OF A 10% ALCOHOL SOLUTION BY MIXING AN UNKNOWN AMOUNT OF A 27% ALCOHOL SOLUTION WITH WATER. HOW MUCH WATER AND HOW MUCH 27% ALCOHOL SOLUTION WILL BE NEED?
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
v%2A27%2F%28500%29=10 where v = how many gallons of the 27% alcohol.
(1) Solve that equation for v.
(2) Expecting to make 500 gallons of the 10% alcohol, letting w = how much water to use, v%2Bw=500 so knowing v, solve for w.