Question 823927: This is a two part equation. The first equation should be to compute the relative distance. The other equation should be to compute the total distance travelled for the same scenario using absolute value.
Scenario 1:
A compact car will drive three miles east, five miles west, and then 13 miles east again. The car gets 40 miles per gallon and there is 1/4 of a gallon of gas left in the tank. Compute the relative distance and the total distance. Then decide if there is enough fuel for the trip.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39625)   (Show Source):
You can put this solution on YOUR website! Miles East: 3+13=16
Miles West: 5
Total Distance moved is 16+5=21, but relative distance is 16-5=11 to the east of the starting point.
21*miles*(1*gallon/(40*miles))=21/40 gallons used for all the movement. Slightly more than half a gallon used.
You did not say the capacity of the gasoline tank. Some cars have a 16 gallon tank. This means (1/4) full is 4 gallons. The driver has plenty of fuel for the trip. If 4 gallons of fuel was in the tank, then using slightly more than half gallon leaves more than 3 gallons still in the tank after the trip.
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
This is a two part equation. The first equation should be to compute the relative distance. The other equation should be to compute the total distance travelled for the same scenario using absolute value.
Scenario 1:
A compact car will drive three miles east, five miles west, and then 13 miles east again. The car gets 40 miles per gallon and there is 1/4 of a gallon of gas left in the tank. Compute the relative distance and the total distance. Then decide if there is enough fuel for the trip.
At 40 miles per gallon,  of a gallon will cover ( ), or 10 miles. That's NOT ENOUGH to cover a distance of
21 (3 + 5 + 13) miles.
You can do the check!!
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