SOLUTION: I need not only answers,but detail solution too The points (-4,0), (-3,-6), (-2, -10) and (1,-10) lie on the curve y = {{{ax^2 + bx + c}}}. Find a, b and c and hence draw the cu

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Question 823880: I need not only answers,but detail solution too
The points (-4,0), (-3,-6), (-2, -10) and (1,-10) lie on the curve y = ax%5E2+%2B+bx+%2B+c. Find a,
b and c and hence draw the curve showing clearly the turning point.

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
A key to a quick solution is noticing that the points (-2, -10) and (1, -10) have the same y-coordinate. Because of the symmetry of parabolas, these two points tells us that the axis of symmetry and the vertex are halfway between -2 and 1:
%28-2%2B1%29%2F2+=+-1%2F2
So the x-coordinate of the vertex is -1/2.

We will use this to build the vertex form, y+=+a%28x-h%29%5E2+%2B+k for the equation of this parabola. (Then we will transform the equation into standard y+=+ax%5E2%2Bbx%2Bc form.) In the vertex form the "h" and the "k" are the x and y coordinates of the vertex. Since we have already found the x-coordinate we can start with:
y+=+a%28x-%28-1%2F2%29%29%5E2+%2B+k
which simplifies to:
y+=+a%28x%2B1%2F2%29%5E2+%2B+k

Next we will substitute in the coordinates of the given points. I'll use (1, -10):
%28-10%29+=+a%28%281%29%2B1%2F2%29%5E2+%2B+k
Simplifying...
-10+=+a%283%2F2%29%5E2+%2B+k
-10+=+a%289%2F4%29+%2B+k
-10+=+%289%2F4%29a+%2B+k
Solving this for k:
-%289%2F4%29a+-+10+=+k

Now we'll repeat this with another point. I'll use (-3, -6):
%28-6%29+=+a%28%28-3%29%2B1%2F2%29%5E2+%2B+k
Simplifying...
-6+=+a%28-5%2F2%29%5E2+%2B+k
-6+=+a%2825%2F4%29+%2B+k
-6+=+%2825%2F4%29a+%2B+k

Now we'll substitute, into this equation, the expression we got earlier for k:
-6+=+%2825%2F4%29a+%2B+%28-%289%2F4%29a+-+10%29
With only the "a" left, we can solve for it. Simplifying...
-6+=+%2816%2F4%29a+-+10%29
-6+=+4a+-+10%29
Adding 10:
4+=+4a%29
Dividing by 4:
1 = a

Now we can use this to find k:
-%289%2F4%29a+-+10+=+k
-%289%2F4%29%281%29+-+10+=+k
-9%2F4+-+40%2F4+=+k
-49%2F4+=+k

Our vertex form is now complete:
y+=+%281%29%28x%2B1%2F2%29%5E2+%2B+%28-49%2F4%29
which simplifies to:
y+=+%28x%2B1%2F2%29%5E2+%2B+%28-49%2F4%29
With h = -1/2 and k = -49/4, the vertex/"turning point" is (-1/2, -49/4).

All that's left is to transform this into standard form. Simplifying...
y+=+%28x%29%5E2%2B2%28x%29%281%2F2%29%2B+%281%2F2%29%5E2+%2B+%28-49%2F4%29
y+=+x%5E2%2Bx%2B+1%2F4+%2B+%28-49%2F4%29
y+=+x%5E2%2Bx%2B+%28-48%2F4%29
y+=+x%5E2%2Bx%2B+%28-12%29