SOLUTION: find all the missing parts of the triangle. given values for angles in terms of radians. A=pi/6 B= 3pi/12 a=2 b=? C=? c=?

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Question 823863: find all the missing parts of the triangle. given values for angles in terms of radians.
A=pi/6
B= 3pi/12
a=2
b=?
C=?
c=?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find all the missing parts of the triangle. given values for angles in terms of radians.
A=pi/6
B=3pi/12
a=2
b=?
C=?
c=?
***
A+B+C=π
C=π-(A+B)=π-(3π/12+π/6)=π-(6π/24+4π/24)=π-10π/24=π-5π/12=7π/12
..
sinC=sin(7π/12)≈0.9659
sinB=sin(3π/12)=sin(π/4)=√2/2
sinA=sin(π/6)=1/2
..
sinA/2=sinB/b
b=2sinB/sinA=(2√2/2)/(1/2)=2√2
..
sinA/2=sinC/c
c=2sinC/sinA==2*0.9659/(1/2)≈4.1412