SOLUTION: (A closed box has a surface area of 126 in. (squared). The base of the box is 5 in. by 3 in. what is the height of the box?) Please show me the work you did to solve it so I can us

Algebra ->  Surface-area -> SOLUTION: (A closed box has a surface area of 126 in. (squared). The base of the box is 5 in. by 3 in. what is the height of the box?) Please show me the work you did to solve it so I can us      Log On


   



Question 823846: (A closed box has a surface area of 126 in. (squared). The base of the box is 5 in. by 3 in. what is the height of the box?) Please show me the work you did to solve it so I can use it as a future reference, thanks.
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Surface area of a box (ie a rectangular prism)

SA = 2*(LW + LH + WH)

126 = 2*(5*3 + 5*H + 3*H)

126 = 2*(15 + 5H + 3H)

126 = 2*15 + 2*5H + 2*3H

126 = 30 + 10H + 6H

126-30 = 10H + 6H

96 = 16H

16H = 96

H = 96/16

H = 6

The height is 6 inches

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(A closed box has a surface area of 126 in. (squared).
The base of the box is 5 in. by 3 in. what is the height of the box?)
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Area of six faces::
2 sides = 2*5*h
2 ends = 2*3*h
top and bottom: 2*3*5
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Equation:
2*5h + 2*3h + 2*15 = 126 in^2
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10h + 6h + 30 = 126
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16h = 96
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height = 6 in
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Cheers,
Stan H.